Reviewed

Fred Fishel
Department of Agronomy

This table is intended to offer the approximate amount of a pesticidal concentrate to be mixed with water to produce sprays for use on the farm and around the home. The desired percentage of active ingredient in the finished spray is obtained by mixing the indicated amount of formulation in 100 gallons of water. The number in parentheses ( ) indicates the amount to use in one gallon of water.

FormulationAmount of formulation to use when desired percent of active ingredient in finished spray is:
0.03125 percent0.0625 percent0.125 percent0.25 percent0.5 percent1.0 percent
Liquid product containing 1 pound chemical per gallon2 pints (2 teaspoons)4 pints (4 teaspoons)1 gallon (8 teaspoons)2 gallons (16 teaspoons)4 gallons (10 tablespoons)8 gallons (2/3 pint)
Liquid productcontaining 1-1/2 pounds chemical per gallon1-1/2 pints (1-1/2 teaspoons)3 pints (3 teaspoons)6 pints (6 teaspoons)1-1/2 gallons (12 teaspoons)3 gallons (7-1/2 tablespoons)6 gallons (1/2 pint)
Liquid product containing 2 pounds chemical per gallon1 pint (1 teaspoons)2 pints (2 teaspoons)4 pints (4 teaspoons)1 gallons (8 teaspoons)2 gallons (5 tablespoons)4 gallons (10 tablespoons)
Liquid product containing 3 pounds chemical per gallon3/4 pint (3/4 teaspoons)1-1/2 pints (1-1/2 teaspoons)3 pints (3 teaspoons)6 pints (6 teaspoons)1-1/2 gallons (4 tablespoons)3 gallons (8 tablespoons)
Liquid product containing 4 pounds chemical per gallon1/2 pint (1/2 teaspoons)1 pint (1 teaspoons)2 pints (2 teaspoons)4 pints (4 teaspoons)1 gallons (8 teaspoons)2 gallons (5 tablespoons)
Liquid product containing 5 pounds chemical per gallon7/16 pint (7/16 teaspoons)7/8 pint (7/8 teaspoons)1-3/4 pints (1-3/4 teaspoons)3-1/2 pints (3-1/2 teaspoons)7 pints (7 teaspoons)1-3/4 gallons (4-1/2 tablespoons)
Liquid product containing 6 pounds chemical per gallon3/8 pint (3/8 teaspoons)3/4 pint (3/4 teaspoons)1-1/2 pints (1/2 tablespoons)3 pints (1 tablespoons)6 pints (2 tablespoons)1-1/2 gallons (4 tablespoons)
Liquid product containing 8 pounds chemical per gallon1/4 pint (1/4 teaspoons)1/2 pint (1/2 teaspoons)1 pint (1 teaspoons)2 pints (2 teaspoons)4 pints (4 teaspoons)1 gallons (8 teaspoons)
15 percent dry product1-2/3 pounds (2-1/2 teaspoons)3-1/3 pounds (5 teaspoons)6-2/3 pounds (20 teaspoons)13-1/3 pounds (7 tablespoons)26-2/3 pounds (1 cup)53-1/3 pounds (2 cups)
25 percent dry product1 pound (1-1/2 teaspoons)2 pounds (3 teaspoons)4 pounds (6 teaspoons)8 pounds (12 teaspoons)16 pounds (1/2 cup)32 pounds (1 cup)
40 percent dry product5/8 pounds (1 teaspoons)1-1/4 pounds (2 teaspoons)2-1/2 pounds (4 teaspoons)5 pounds (8 teaspoons)10 pounds (5 tablespoons)20 pounds (10 tablespoons)
50 percent dry product1/2 pound (3/4 teaspoons)1 pound (1-1/2 teaspoons)2 pounds (3 teaspoons)4 pounds (6 teaspoons)8 pounds (4 tablespoons)16 pounds (1/2 cup)
80 percent dry product5 ounces (1/2 teaspoons)10 ounces (1 teaspoons)1-1/4 pounds (2 teaspoons)2-1/2 pounds (4 teaspoons)5 pounds (8 teaspoons)10 pounds (5 tablespoons)
Some helpful equivalents
  • 1 tablespoon (Tbs) = 3 teaspoons (tsp)
  • 1 cup = 16 Tbs
  • 1 cup = 8 fluid ounces (fl oz)
  • 1 tablespoon = 1/2 fluid ounce
  • 2 cups = 1 pint (pt)
  • 2 pints = 1 quart (qt)
  • 4 quarts = 1 gallon (gal)
  • 1 pound = 16 ounces (oz)
  • water weighs 8.3 pounds per gallon

Pesticide dilution formulas and examples

Formula 1

To determine how many gallons of emulsifiable concentrate are needed to mix a spray containing a given percentage of active ingredient:

(gallons of spray wanted) x ( percent active ingredient wanted) x (8.3 pounds per gallon)
(pounds active ingredient per gallon of concentrate) x (100)

Example
How many gallons of diazinon 25 percent emulsifiable concentrate (2 pounds diazinon per gallon) are needed to make 100 gallons of spray containing 0.5 percent diazinon?

(100 x 0.5 x 8.3) ÷ (2 x 100) = 2 gallons (rounded off)

Formula 2

To determine how many pounds of wettable powder needed to mix a spray containing a given percentage of active ingredient:

(gallons of spray wanted) x ( percent active ingredient wanted) x (8.3 pounds per gallon)
(percent active ingredient in insecticide used)
= 21 pounds(rounded off)

Example
How many pounds of carbaryl (Sevin) 50 percent wettable powder are needed to make 100 gallons of spray containing 1.25 percent carbaryl?

(100 x 1.25 x 8.3) ÷ 50 = 20.0 pounds (rounded off)

Formula 3

To determine the percentage of active ingredient in a spray mixture:

(pounds insecticide used) x ( percent active ingredient)
(gallons of spray mixture) x (8.3 pounds per gallon)

Example
Eight pounds of carbaryl (Sevin) 50 percent wettable powder were mixed in 100 gallons of water. What percentage of carbaryl did the finished spray contain?

(8 x 50) ÷ (100 x 8.3) = 0.48 percent